Here's how to win roulette, 100% of the time...
If you repeat the same red/black bet over and over, you have a 100% probability of eventually getting a win, and if you apply my bet placement technique correctly, your win will always be bigger than your accumulated losses, so you always come out ahead!
Let me explain - if you lose the first red/black bet, you make the same play again but this time you double your bet. The idea is to win enough this time to cover the loss on the first bet. If you lose again, you make the same play again and you double again in the same way.
When you play the same red/black bet over and over and double your bet to cover your losses until you win, you are always going to come out ahead ... THAT SIMPLE MATHEMATICAL FACT CAN MAKE YOU THOUSANDS! Here are some examples:
Let me explain - if you lose the first red/black bet, you make the same play again but this time you double your bet. The idea is to win enough this time to cover the loss on the first bet. If you lose again, you make the same play again and you double again in the same way.
When you play the same red/black bet over and over and double your bet to cover your losses until you win, you are always going to come out ahead ... THAT SIMPLE MATHEMATICAL FACT CAN MAKE YOU THOUSANDS! Here are some examples:
Note: the process of 'doubling until you win' is referred to here as a 'betting cycle'.
Example betting cycle:
Example betting cycle:
Spin 1 - Start with $1 on RED, the ball lands on BLACK so you lose $1.
Spin 2 - Double to $2 on RED, the ball lands on BLACK so you lose $2, making $3 lost in total.
Spin 3 - Double to $4 on RED, the ball lands on BLACK so you lose $4, making $7 lost in total.
Spin 4 - Double to $8 on RED, the ball lands on RED so you win $8.
Spin 2 - Double to $2 on RED, the ball lands on BLACK so you lose $2, making $3 lost in total.
Spin 3 - Double to $4 on RED, the ball lands on BLACK so you lose $4, making $7 lost in total.
Spin 4 - Double to $8 on RED, the ball lands on RED so you win $8.
So in this betting cycle you lost $7 but you won $8. It's a mathematical fact that no matter how long or short a betting cycle is, you always come out ahead by the amount of your first bet when you use this technique.
Example betting cycle:
Spin 1 - First you bet $1 on RED, the ball lands on RED so you win $1.
You're $1 up!
You're $1 up!
Example betting cycle:
Spin 1 - First you bet $1 on RED, the ball lands on GREEN so you lose $1.
Spin 2 - Put $2 on RED, the ball lands on RED so you win $2.
You're $1 up!
Spin 2 - Put $2 on RED, the ball lands on RED so you win $2.
You're $1 up!
Example betting cycle:
Spin 1 - First you bet $1 on RED, the ball lands on BLACK so you lose $1.
Spin 2 - Put $2 on RED, the ball lands on BLACK so you lose $2, making $3 lost in total.
Spin 3 - Put $4 on RED, the ball lands on RED so you win $4.
You're $1 up!
Spin 2 - Put $2 on RED, the ball lands on BLACK so you lose $2, making $3 lost in total.
Spin 3 - Put $4 on RED, the ball lands on RED so you win $4.
You're $1 up!
So as you can clearly see, you always come out ahead by the amount of your first bet regardless of how long or short the cycle is. In fact betting cycles are usually short, for example the odds of getting just 4 of the same colour in a row are 16 to 1.
To start a new cycle you simply repeat the procedure starting with $1 on the opposite colour. For example, when you've won a cycle on reds, play your next cycle on blacks, then the cycle after that on reds again and keep alternating.
Winning $1 doesn't sound much but I usually get through 3 or 4 average length cycles per minute. Do the math,that's $150-$200 of clear profit per hour, and that's with only $1 bets.
Using this technique is completely legal and the risks are almost non-existent if you follow these three golden rules:
- Start each new cycle with a $1 bet.
- If you lose, put your next bet on the same colour and double it.
- If you win, start a new cycle with a $1 bet on the opposite colour.
